Q&A: What’s the Intuition Behind the Order of Function Transformations?
Cross-posted from here.
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Question
Is there a good intuitive explanation for how to think about the order of steps when graphing functions through a sequence of transformations?
Answer
One way to build intuition around this is to think about the effects on the intercepts.
Vertical Shifts/Stretches: Effect on $y$-Intercept
Suppose you want to graph $y=2\sqrt{x}-6$ using transformations.
You know the result needs to have a $y$-intercept of $-6$ (which comes from evaluating $2\sqrt{0}-6$).
- If you stretch vertically by a factor of $2$ and then shift $6$ down, you get a $y$-intercept of $-6$ as desired. $\color{green}\checkmark$
- If you shift $6$ down and then stretch vertically by a factor of $2,$ you get a $y$-intercept of $-12$ which is incorrect. $\color{red}\times$
So vertical stretches come before vertical shifts.
Horizontal Shifts/Shrinks: Effect on $x$-Intercept
Suppose you want to graph $y=\sqrt{2x-6}$ using transformations.
You know the result needs to have an $x$-intercept of $3$ (which comes from solving $0=\sqrt{2x-6}$).
- If you shrink horizontally by a factor of $2$ and then shift $6$ right, you get an $x$-intercept of $6$ which is incorrect. $\color{red}\times$
- If you shift $6$ right and then shrink horizontally by a factor of $2,$ you get an $x$-intercept of $3$ as desired. $\color{green}\checkmark$
So horizontal shifts come before horizontal shrinks.
More Hand-Wavy (But Potentially More Memorable) Intuition
When it comes to horizontal transformations, everything works the opposite way as vertical transformations.
The transformations themselves are opposite:
- shifts right (the negative horizontal direction) instead of shifts up (the positive vertical direction)
- horizontal shrinks instead of vertical stretches
So it’s kind of intuitive that the order of transformations is also opposite.
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